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	Use path not filepath in template filenames (#21993)
Paths in git are always separated by `/` not `\` - therefore we should `path` and not `filepath` Fix #21987 Signed-off-by: Andrew Thornton <art27@cantab.net> Co-authored-by: Lunny Xiao <xiaolunwen@gmail.com> Co-authored-by: Lauris BH <lauris@nix.lv>
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		| @@ -6,7 +6,7 @@ package template | ||||
| import ( | ||||
| 	"fmt" | ||||
| 	"io" | ||||
| 	"path/filepath" | ||||
| 	"path" | ||||
| 	"strconv" | ||||
|  | ||||
| 	"code.gitea.io/gitea/modules/git" | ||||
| @@ -43,7 +43,7 @@ func Unmarshal(filename string, content []byte) (*api.IssueTemplate, error) { | ||||
|  | ||||
| // UnmarshalFromEntry parses out a valid template from the blob in entry | ||||
| func UnmarshalFromEntry(entry *git.TreeEntry, dir string) (*api.IssueTemplate, error) { | ||||
| 	return unmarshalFromEntry(entry, filepath.Join(dir, entry.Name())) | ||||
| 	return unmarshalFromEntry(entry, path.Join(dir, entry.Name())) // Filepaths in Git are ALWAYS '/' separated do not use filepath here | ||||
| } | ||||
|  | ||||
| // UnmarshalFromCommit parses out a valid template from the commit | ||||
| @@ -108,7 +108,7 @@ func unmarshal(filename string, content []byte) (*api.IssueTemplate, error) { | ||||
| 			// It could be a valid markdown with two horizontal lines, or an invalid markdown with wrong metadata. | ||||
|  | ||||
| 			it.Content = string(content) | ||||
| 			it.Name = filepath.Base(it.FileName) | ||||
| 			it.Name = path.Base(it.FileName) // paths in Git are always '/' separated - do not use filepath! | ||||
| 			it.About, _ = util.SplitStringAtByteN(it.Content, 80) | ||||
| 		} else { | ||||
| 			it.Content = templateBody | ||||
|   | ||||
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